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12m^2-10m=24
We move all terms to the left:
12m^2-10m-(24)=0
a = 12; b = -10; c = -24;
Δ = b2-4ac
Δ = -102-4·12·(-24)
Δ = 1252
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1252}=\sqrt{4*313}=\sqrt{4}*\sqrt{313}=2\sqrt{313}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{313}}{2*12}=\frac{10-2\sqrt{313}}{24} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{313}}{2*12}=\frac{10+2\sqrt{313}}{24} $
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